Question

sat?
what we will do multiplying their Derivatives? sat?
what we will do multiplying their Derivatives? @Mathematics

Answer 1

\[90 u^{44} x (3 x-4)\]
After this it says some substituion!! >_<

Answer 2

what??

Answer 3

I mean, it's easier than it appears to be

Answer 4

you have
\[y=u^{45}\] and also
\[u=2x^3-4x^2\] which means
\[y=(2x^3-4x^2)^{45}\]

Answer 5

Yes

Answer 6

this is not a multiplication, it is a composition

Answer 7

Oh, yeah, safoo was confused

Answer 8

and the derivative os
\[y'=45(2x^3-4x^2)^{44}\times (6x^2-8x)\]

Answer 9

after we find it's derivatives, it says substituting the value for u.

Answer 10

right , they are trying to show you the chain rule as if you are an idiot, leading you through step by step. unnecessary

Answer 11

what they want you to write is
\[\frac{dy}{du}=45u^{44}\]
\[\frac{du}{dx}=6x^2-8x\] and so
\[\frac{dy}{dx}=\frac{dy}{du}\times \frac{du}{dx}=45u^{44}(6x^2-8x)=45(2x^3-4x^2)^{44}\times (6x^2-8x)\]

Answer 12

don't go for it just use the chain rule and be done

Answer 13

Thanks for that one.