Question

How many times does the graph of y = x + 1 intersect the graph of y = x^2 + 3?
Answer

a. 1

b. 2

c. 3

d. 0 How many times does the graph of y = x + 1 intersect the graph of y = x^2 + 3?
Answer

a. 1

b. 2

c. 3

d. 0 @Mathematics

Answer 1

I'm assuming y =–x2+3 means y=-x²+3

They are asking.. if the two equations equal each other how many solutions are there?
-x²+3 = x+1

Put it all on one side:
0=x+1+x²-3
0=x²+x-2

x²+x-2=0
Solve the quadratic by factoring:
(x-1)(x+2)=0
So x=1 or x=-2

Answer: Two times at x=1 and again at x=-2.

Answer 2

Thanks

Answer 3

no Problem

Answer 4

Wait, you shouldn't have three solutions... because that would imply that the function x + 1 - x^2 + 3 had three zeros which can't happen by the fundamental theorem of algebra

Answer 5

sorry, x + 1 + x^2 - 3