Question

VHDL: How do I mask a generic n-bit to the least significant bit?

Answer 1

I already solved it!

Answer 2

x & 0x01

Answer 3

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signal zero, one: bit_vector(w-2 downto 0);
begin
zero <= (others => '0');
one<=(zeros & "1");

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Answer 4

I didnt undertand dmancine. Could you explain in other words? Thx

Answer 5

I don't know VHDL (or even what it is), but that's how you'd do it in most modern programming languages.

x is the variable you want to find the LSB of
& is the bitwise AND operator
0x means the following numeric literal is in hexadecimal
01 is the hex value for a mask with just the LSB on

So, it will zero-out all the bits of x except the LSB, which it will copy from x. Thus, the result will be just the LSB of x.

I don't know if that's exactly what you were asking. And I really don't know what the VHDL would look like. I was kinda' being a smartass. ;)

Answer 6

VHDL is a Hardware description Laguage used to document and simulate digital circuits.

I use the technique you mentioned above in Assembly language...