I'll put the bases into () . Solve log(1-x)3-log(1-x)2-0,5=0
log(1-x)3 - log(1-x)2 - 0.5 = 0 log(1-x)3/2 = 0.5 : : Combine log functions using log properties and move 0.5 to other side (1-x)^0.5 = 3/2 : : (1-x) is the base with the exponent being 0.5 (1-x) = (3/2)^2 : : 0.5 exponent is the same as square rooting it x = 1 - (3/2)^2
Thank you !
no problem
I have on more problem , if you have time .
sure
Log(x)log(2x)2=log(4x)2
And also , do you have any idea on how to solve (1-x)^4
if i knew what is on the other side of the equation... that other log problem is tricky
Other side is x^2
(1-x)^4=x^2
((1-x)^2)^2 = x^2 (1-x)^2 = x 1-x = +- x ^(1/2) 0 = +- x^(1/2) + x - 1 ... i got stuck here
Okay , but what about that first one?
that one involves a property of logs that i can't remember... sorry about that. Try going over the properties of logs
Okay , thank you so much for your time !
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