I'll put the bases into () . Solve log(1-x)3-log(1-x)2-0,5=0
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OpenStudy (anonymous):
log(1-x)3 - log(1-x)2 - 0.5 = 0
log(1-x)3/2 = 0.5 : : Combine log functions using log properties and move 0.5 to other side
(1-x)^0.5 = 3/2 : : (1-x) is the base with the exponent being 0.5
(1-x) = (3/2)^2 : : 0.5 exponent is the same as square rooting it
x = 1 - (3/2)^2
OpenStudy (anonymous):
Thank you !
OpenStudy (anonymous):
no problem
OpenStudy (anonymous):
I have on more problem , if you have time .
OpenStudy (anonymous):
sure
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OpenStudy (anonymous):
Log(x)log(2x)2=log(4x)2
OpenStudy (anonymous):
And also , do you have any idea on how to solve (1-x)^4
OpenStudy (anonymous):
if i knew what is on the other side of the equation... that other log problem is tricky
OpenStudy (anonymous):
Other side is x^2
OpenStudy (anonymous):
(1-x)^4=x^2
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OpenStudy (anonymous):
((1-x)^2)^2 = x^2
(1-x)^2 = x
1-x = +- x ^(1/2)
0 = +- x^(1/2) + x - 1
... i got stuck here
OpenStudy (anonymous):
Okay , but what about that first one?
OpenStudy (anonymous):
that one involves a property of logs that i can't remember... sorry about that.
Try going over the properties of logs