2/5h+g=d, for h
Isolate h using legal algebraic operations. Subtract g from both sides of equal sign getting 2/5h=d-g Now I need to clarify is it 2/(5h) or is it (2h)/5 ???
It just says 2/5h Idk why it is harder for me when you are solving for specific variable when its numbers its really easy for me
If it is (2h)/5) or 2/5 h, then multiply all terms by 5/2 getting h=5/2 (d-g) if it is 2/5h (2 divided by 5h) then you would do this. multiply all terms by 5h getting: 2=5h(d-g) now divide terms by 5(d-g) getting 2/(5(d-g) =h or \[2 \over5(d-g)\]
ummm im pretty sure if you have 2/5h+g=d then you would -g first....to get the specific variable ???
There is a big difference if h is in denominator or not. \[2\over5h\]is a lot different than\[2h \over 5\]
Yes, I subtracted the g in the first post
omg i didnt know that i just typed what was in my workbook im only a freshman
I had to run. Good luck with it, and post often when u r having difficulty.
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