Question

i hate dividing these thingies!
(g^2+8g+15)(g+3)^-1 i hate dividing these thingies!
(g^2+8g+15)(g+3)^-1 @Mathematics

Answer 1

It smultiplying no dividing

Answer 2

no..its dividing cuz its raised to a -1

Answer 3

\[(g^{2}+8g+15)/(g+3)\]

Answer 4

(g+5) is the amswer

Answer 5

okay...wood u mind explaining tat?

Answer 6

\[(g^{2}+8g+15)=(g+5)(g+3)\]

Answer 7

you can factor the numerator to: (g+5)(g+3)/(g+3)

Answer 8

i suck at factoring..so can u find me an easier method?

Answer 9

That is the only way to do it

Answer 10

r u sure? cuz my txt book shows a lot of methods but none really fit me...