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How does 5k=2(mod 7) equal k=6(mod 7) ?
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k in an integer btw
k is a*
because if \[5k\equiv 2(\text{mod} 7)\] then also \[5k\equiv 2+4\times 7=30(\text{mod} 7)\] and so \[k\equiv 6(\text{mod} 7)\]
well if u multiply the 2nd by 5, we get 5k = 30 (mod7)....but 30 (mod 7) is 2 (mod 7)
also what qed said!
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ty
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