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Mathematics 13 Online
OpenStudy (anonymous):

How do I go about taking the derivative of the square root of (5x+6)? I know it is also equivalent to (5x+6)^1/2 then chain rule, but according to web work my process is wrong. Thanks! How do I go about taking the derivative of the square root of (5x+6)? I know it is also equivalent to (5x+6)^1/2 then chain rule, but according to web work my process is wrong. Thanks! @Mathematics

jimthompson5910 (jim_thompson5910):

sqrt(5x+6) (5x+6)^1/2 Derive this to get (1/2)(5x+6)^(-1/2)*d/dx(5x) (5/2)(5x+6)^(-1/2) 5/(2(5x+6)^(1/2)) 5/(2*sqrt(5x+6)) So the derivative is \[\Large \frac{5}{2\sqrt{5x+6}}\]

jimthompson5910 (jim_thompson5910):

oops meant to type d/dx(5x+6), but you get the same answer anyway

OpenStudy (anonymous):

Thanks I appreciate it!

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