Question

Simplify (-3+6i)/(-1+i)

Answer 1

does "simplify" mean "write in standard form as
\[a+bi\]? is so, multiply top and bottom by the conjugate of the denominator

Answer 2

yes

Answer 3

what do u mean by conjugate?

Answer 4

\[(a+bi)(a-bi)=a^2+b^2\] a real number. so in your case you want
\[\frac{-3+6i}{-1+i}\times \frac{-1-i}{-1-i}=\frac{(-3+6i)(-1-i)}{1^2+1^2}\]

Answer 5

all the work is multiplying in the numerator. the denominator is 2

Answer 6

do i multiply the top out?

Answer 7

yes you have to multiply out in the numerator

Answer 8

when you are all through you should get
\[\frac{9-3i}{2}\] which in standard form is
\[\frac{9}{2}-\frac{3}{2}i\]