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Use algebra to find the inverse of the given one-to-one function. f(x)=5+(square root of 2x -5)
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\[f(x)=5+\sqrt{2x-5}\]
x=((y-5)^2+5)/2
did you get it?
thats wronf according to my hw site
*wrong
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\[f ^{-1}(x)=\]
the answer should look like this
hey where'd u go? lol
replace y with x
that is correct! :D could you show me the steps please so i can write them down?
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let us say f(x)=y. y-5=sqrt(2x-5) (y-5)^2=2x-5 [squaring on both sides..] solve for x from here on..
ok thanks. i need help with another one so if u can, please help. thanks again.
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