The problem I am working on is x^2+10x+y+20=0 I need to find the standard form of the equation of this parabola.
I come up with 2 answers not sure which is right y=(x+5)^2-5 or y=(x-5)^2+5

Question

The problem I am working on is x^2+10x+y+20=0 I need to find the standard form of the equation of this parabola. 
 I come up with 2 answers not sure which is right y=(x+5)^2-5   or  y=(x-5)^2+5

anonymous · Answer

Actually, neither is quite correct Josephxxx773... you needed to get the x's and y's on separate sides of the equation so you are missing a negative in there.  y=-(x=5)^2 +5 but you're close on both accounts!  :)

myininaya · Answer

$$y=-x^2-10x-20=-(x^2+10x)-20=-(x^2+10+5^2)-20+25   $$
=-(x+5)^2+5

anonymous · Answer

Ooops - typo in that last post...  y=-(x+5)^2+5

anonymous · Answer

Thanks I am having a rely tough time with this. 
Joseph