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Calculus1 14 Online
OpenStudy (anonymous):

h(x)=f(g(x)) Find h'(1) How would I do this? @Mathematics

OpenStudy (anonymous):

it would be \[f'(g(1))\times g'(1)\] so if you knew those numbers you could compute it.

OpenStudy (anonymous):

Thanks for your help

OpenStudy (anonymous):

I guess they wanted it like this because they didn't give any other values

OpenStudy (anonymous):

if you don't have the numbers or the functions there is nothing you can compute

OpenStudy (anonymous):

This is just the chain rule

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

what is the function you need to find H prime of?

OpenStudy (anonymous):

They didn't give a function so I was getting confused but I guess they wanted the basic steps of the chain rule. I don't know my textbook can be very confusing

OpenStudy (anonymous):

Ohh there pretty much asking for this H'(x) = f '(g(x)) g '(x)

OpenStudy (anonymous):

ya but reaplacing the x with 1

OpenStudy (anonymous):

yeah exactly

OpenStudy (anonymous):

Stupid

OpenStudy (anonymous):

this calc 2?

OpenStudy (anonymous):

nope calc 1

OpenStudy (anonymous):

I am in calc 3, its Calc 1, but with multiple variables soo...chain rule on a function with (X,Y,Z) variables, not bad good luck

OpenStudy (anonymous):

Sounds pretty scary. I have another few months and I will also be taking calc3 YIKES

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