h(x)=f(g(x))
Find h'(1)
How would I do this? @Mathematics
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OpenStudy (anonymous):
it would be
\[f'(g(1))\times g'(1)\] so if you knew those numbers you could compute it.
OpenStudy (anonymous):
Thanks for your help
OpenStudy (anonymous):
I guess they wanted it like this because they didn't give any other values
OpenStudy (anonymous):
if you don't have the numbers or the functions there is nothing you can compute
OpenStudy (anonymous):
This is just the chain rule
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OpenStudy (anonymous):
yup
OpenStudy (anonymous):
what is the function you need to find H prime of?
OpenStudy (anonymous):
They didn't give a function so I was getting confused but I guess they wanted the basic steps of the chain rule. I don't know my textbook can be very confusing
OpenStudy (anonymous):
Ohh there pretty much asking for this
H'(x) = f '(g(x)) g '(x)
OpenStudy (anonymous):
ya but reaplacing the x with 1
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OpenStudy (anonymous):
yeah exactly
OpenStudy (anonymous):
Stupid
OpenStudy (anonymous):
this calc 2?
OpenStudy (anonymous):
nope calc 1
OpenStudy (anonymous):
I am in calc 3, its Calc 1, but with multiple variables soo...chain rule on a function with (X,Y,Z) variables, not bad good luck
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OpenStudy (anonymous):
Sounds pretty scary. I have another few months and I will also be taking calc3 YIKES