(20)/(x-10)-(3)/(10-x) reduce if possible, assume that no denominator is 0. I need the steps please, thank you.

Question

anonymous · Answer

Distribute the 20 and the -3 and simplify

asnaseer · Answer

you should spot that the denominator of the 2nd fraction is just the negative of the denominator of the 1st fraction so that this can be re-arranged as follows:$$\frac{20}{x-10}-\frac{3}{10-x}=\frac{20}{x-10}-\frac{3}{-(x-10)}$$$$=\frac{20}{x-10}+\frac{3}{x-10}$$you should then be able to solve this fairly simply...

anonymous · Answer

^^ thats easier lol

asnaseer · Answer

it helps to gaze at a problem for a bit before diving into it.

asnaseer · Answer

@Cierra-Nicole - do you understand how to complete this problem now?

anonymous · Answer

yes and no - i have a another problem, i need the complete breakdown.?

anonymous · Answer

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