A 5.05-kg block is placed on top of a 11.7-kg block that rests on a frictionless table. The coefficient of static friction between the two blocks is 0.685. What is the maximum horizontal force that can be applied before the 5.05-kg block begins to slip relative to the 11.7-kg block, if the force is applied to the more massive block?
A 5.05-kg block is placed on top of a 11.7-kg block that rests on a frictionless table. The coefficient of static friction between the two blocks is 0.685. What is the maximum horizontal force that can be applied before the 5.05-kg block begins to slip relative to the 11.7-kg block, if the force is applied to the more massive block?
@Mathematics

Question

A 5.05-kg block is placed on top of a 11.7-kg block that rests on a frictionless table. The coefficient of static friction between the two blocks is 0.685. What is the maximum horizontal force that can be applied before the 5.05-kg block begins to slip relative to the 11.7-kg block, if the force is applied to the more massive block?
 A 5.05-kg block is placed on top of a 11.7-kg block that rests on a frictionless table. The coefficient of static friction between the two blocks is 0.685. What is the maximum horizontal force that can be applied before the 5.05-kg block begins to slip relative to the 11.7-kg block, if the force is applied to the more massive block?
 @Mathematics

anonymous · Answer

i think its114.73N.just draw the fbd and apply the criteria for no slip i.e f<=coff. of friction*normal rkn