Question

2x^2+3=2x 2x^2+3=2x @Mathematics

Answer 1

Solve completely with Complex numbers

Answer 2

\[2x^2-2x+3=0\]
\[D=4-4*3*2=-20\]
\[x1,2=(2+-\sqrt{-20})/4=(1+-\sqrt{5i^2})/2=(1+-i \sqrt{5})/2\]

Answer 3

So the answer isn't:

\[x=\frac{1}{2} \pm 1 \frac{\sqrt{5}}{2}i\]

Answer 4

its the same as i wrote, just written in other form

Answer 5

Ahh... OK couldn't tell, I was confused.