Question

Write the linear function for the line with slope 5/4 that passes through the point (-4, 1) and graph the function. Please show all of your work Write the linear function for the line with slope 5/4 that passes through the point (-4, 1) and graph the function. Please show all of your work @Mathematics

Answer 1

The equation of a line in slope-intercept form is y=mx+b

You know that the slope is 5/4, so you can just rewrite the equation as
y=(5/4)x+ b
Then you just have to find b. To find b, plug in the point you are given, put -4 for x and 1 for y and solve for b.
To graph the function, you can plug in numbers and just connect the dots.

Answer 2

I dont understand how to solve for b

Answer 3

The point (-4,1) represents (x,y). To find the linear function, all you have to do is plug in the x and the y into your equation. So when you have y=(5/4)x+b you can put
1=(5/4)(-4)+b. After you simplify this, move the number to one side and make it equal to b. That b is your b for the equation.

Answer 4

ok, so b = -5 ? Is this correct?

Answer 5

Close, (5/4) times (-4) is -5, but you can't forget about the 1 you have on the other side of your equation. So at that step, you have 1=-5+b
To solve for b, you have to move -5 over to the other side, so you get
6=b

Answer 6

ok so how would I graph this then?

Answer 7

IM so confused

Answer 8

Think about your equation as a machine. You put in an y and it gives you an x, or you can put in an x and it gives you a y.
For example, if I say x=1 (just a random number, any will work)
Y=(5/4)1+6
After you simplify you get y=29/4
So a point on your graph is (1,(29/4))
However, it's easier to use whole numbers.
You can use the point you already have (-4,1) and just go from there.
Plot (-4,1) and make another point 5 points above (-4,1) and 4 points to the right of it

Answer 9

does the graph look something like this?