Two fire towers are 30 kilometers apart, tower A being due west of tower B. A house fire is spotted from the towers, and the bearings from A and B are N 72◦ E and N 52◦ W, respectively. Find the distance d of the fire from the line segment AB. Answer in units of km
tan 38 = d / x tan 18 = d / (30-x) solve these two equations simultaneously to find values of x and d.
from first equation: x = d / tan 38 plug this into second equation and solve for d
tan18= 30/tan38 ?
tan18 = d / ( 30 - d/tan38) tan18 = d / (30tan38 - d) / tan38 tan 18 = d * tan 38 ------- 30tan38 - d d tan38 = 30tan38tan18 - dtan18 d = 30tan38tan18 ------------ tan38 + tan 18 = 7.61565 / 1.10621 = 6.88 km
the algebra's a bit messy
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