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Solve. 3x^2 – 7x – 2 = 0
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\[x=-5\pm \sqrt{13}/2 \]
\[x=-3\pm \sqrt{13}\]
\[1x=-5\pm \sqrt{37}/2\]
\[x=5\pm \sqrt{13}/2\]
these are the answers given to choose from
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x = [7 +- sqrt(49 - 4*3*-2)] / 6 = [ 7 +- sqrt73 ] / 2
jimmy do u mean 37 cause they dont give an answer with sqrt 73
mathmind can u help me with this please
if you have an equation \[ax^2+bx+x=0\] use the quadratic equation to solve for x:\[Xroots= \frac{-b \pm \sqrt{b^2-4ac}}{2a} \] does that help ?
sorry the first equation should be:\[ax^2+bx+c=0\]
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is right the jimmyrep's answer just from last fraction the denominator is 6 and not is 2
right jhony - the denominator is 2*3 = 6
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