Question

help me prove that
tanx(csc^2x-1) /sinx + ((cosx)(cotx))= cosx

Answer 1

sinx=1/cscx
cosx=1/secx
tanx=1/cotx
this works the other way too
1/sinx=cscx
1/cosx=secx
1/tanx=cotx
Also, tangent is sine over cosine, so it follows that cotx=cosx/sinx

I hope that helps you out. Also, don't forget that it applies to this:
sinx+cosx=1
if you divide both sides by cosx you get
tanx+1=secx
or if you divided by sinx on both sides you get
1+cotx=cscx

Answer 2

help me solve it! thank you