Question

Find the value of x.
A right triangle is drawn with an altitude from the right angle to the side opposite the right angle. The altitude breaks the side opposite into two segments. The first segment is labeled 2 units. The other segment is labeled 10 units. The altitude is labeled x.

2.5

5 times the square root of 2.

5

2 times the square root of 5. Find the value of x.
A right triangle is drawn with an altitude from the right angle to the side opposite the right angle. The altitude breaks the side opposite into two segments. The first segment is labeled 2 units. The other segment is labeled 10 units. The altitude is labeled x.

2.5

5 times the square root of 2.

5

2 times the square root of 5. @Mathematics

Answer 1

sqrt(78)

Answer 2

Solve the following for x:\[\left(2^2+x^2\right)+\left(10^2+x^2\right)= (2+10)^2\]\[x=+-2 \sqrt{5} \]\[x=2 \sqrt{5} \]