Question

how do you solve x(x^2-x-2), [-1,1] using the mean value theorem

Answer 1

this question is ill posed. do you mean "what does the mean value theorem say about the function
\[f(x)=x(x^2-x-2)\] over the interval [-1,1]?

Answer 2

\[\frac{f(1)-f(-1)}{1--1}=f'(c)\]

Answer 3

or does it mean "find the value of c so that
\[f'(c)=\frac{f(1)-f(-1)}{2}\]

Answer 4

i assume of course the second :)

but yeah, it could mean the slope obtained ....