Can you help me see where I am stuck finding the zeros of this quadratic equation?

Question

anonymous · Answer

$$3x^2 - 12x + 11 = 0$$

anonymous · Answer

quadratic formula for this one 
use 
$$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$ with 
$$a=3,b=-12,c=11$$

anonymous · Answer

My student solutions manual says I should obtain $$(6 \pm \sqrt{3}) \div 3$$

anonymous · Answer

indeed you should

anonymous · Answer

Let's walk through this, so I can see where I am tripping over my shoelaces.

anonymous · Answer

first you get 
$$\frac{-12\pm\sqrt{(-12)^2-4\times 3\times 11}}{6}$$

anonymous · Answer

Wait a sec. I see that I made an error in the first term under the radical.  I will go back to the drawing board and re-attempt this one on my own.

anonymous · Answer

By the way, how are you producing the nice looking divisor line?

anonymous · Answer

\frac{a}{b} looks like 
$$\frac{a}{b}$$

anonymous · Answer

Got it.  I made simple mistakes in my substitutions, then got hung up on trying to do algebra with unduly complicated figures.

anonymous · Answer

THANKS @satellite73, you got me unstuck!