Question

Here is another radical equation, this one is a bit different than the others

Answer 1

\[\sqrt{-3x+16}-1=\sqrt{-2x+9}\]

Answer 2

I'm confused about the 1 in the middle mostly

Answer 3

x^ 2 - 10x + 32 = 0
u will get this

then solve it

Answer 4

so do i factor it?

Answer 5

1st square both side of the equation,

Answer 6

-3x + 16 + 1 - 2( -3x +16)^0.5 = -2x + 9

-x + 8 -2 (-3x +16)^0.5 = 0

8-x = 2 (-3x +16)^0.5

square both side again

64 - 16x + x^2 = 2(-3x+16)

= -6x +32
32 -10 + X^2 = 0

factorise this