Question

solve the systems of equations
16x^2+4y^2=64
x^2-4=y

Please show work
solve the systems of equations
16x^2+4y^2=64
x^2-4=y

Please show work
@Mathematics

Answer 1

muliply the second equation by -16

Answer 2

I tried that but it becomes very strange

Answer 3

why not substitute x^2-4 for y in the first equation? it will get a little messy, but not unbearable.

Answer 4

One sec, I'll try

Answer 5

I get y=-4, one sec

Answer 6

x would have to be 0 in that case. So (0,-4) is one solution. There are 2 more than i can see though.

Answer 7

got one, (2,-4)

Answer 8

another, (-2,-4)

Answer 9

and yours is the third :)

Answer 10

Is that it? 3?

Answer 11

(2,-4) doesnt work though. that would mean:\[x^2-4=y\iff (2)^2-4=-4\iff 4-4=-4\]

Answer 12

(0, -4) is a solution though. The other ones I see are (-2,0) and (2,0). Im not sure if there are any others.

Answer 13

Thanks

Answer 14

(0,-4) doesn't work in the long equations

Answer 15

nevermind