Question

consider the function g(x)=(x^4+1)/x^3+x^2

We have computed the first derivative, and we found that the only values of x for which g'(x)=0 are x=-2.2, x=-0.6, x=1.15. Also g'(1000)>0 and g'(-1000)>0. Use this information, your knowledge of the asymptotes from the previous question, and whatever else you need to sketch the graph of g. From this particular question, you do not have to look at concavity. consider the function g(x)=(x^4+1)/x^3+x^2

We have computed the first derivative, and we found that the only values of x for which g'(x)=0 are x=-2.2, x=-0.6, x=1.15. Also g'(1000)>0 and g'(-1000)>0. Use this information, your knowledge of the asymptotes from the previous question, and whatever else you need to sketch the graph of g. From this particular question, you do not have to look at concavity. @Mathematics

Answer 1

i wish people would use parentheses. do you mean (x^4 + 1)/(x^3 + x^2)?

Answer 2

yes

Answer 3

well, there's two vertical asymptotes, x = 0 and x = -1

Answer 4

yeh i know that there is also y=x which is slant asymptote and there is no horizontal asymptote.

Answer 5

Then?