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3+sqrt{z-1} =sqrt{z+14} 3+sqrt{z-1} =sqrt{z+14} @Mathematics
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\[3+\sqrt{z-1 }= \sqrt{z+14}\]
z=2 but the way I got there.... I don't think you would know...
\[3+\sqrt{z-11} = \sqrt{z+4}\]
i got 2.
i have to square both terms then use foil
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im just making sure they are correct cause i always make mistakes
i have no clue how i posted the other problem
\[3+\sqrt{z-11} = \sqrt{z+4}\] \[z=12\] I've been using using phasor form and de moivre's
oh yea i dont know what that is lol
basically, it's a quicker route then trying to get everything to FOIL correctly... but it involves switching to sin and cos ... which can be a bit more difficult if you're not used to it.
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oh yea i would totally get lost lol i have a hard time doing this darn math
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