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Mathematics 15 Online
OpenStudy (aravindg):

prob @Physics

OpenStudy (aravindg):

A wire 10 m long is cut into 2 parts. One part is bent into the shape of a circle and other into shape of equilateral triangle .How should the wire be cut so that the combined area of two figures is as small as possible???

OpenStudy (jamesj):

Suppose the two lengths are A and B. Write down for me the equation for the area of the circle in terms of A and then the equation for the area of the triangle in terms of B.

OpenStudy (aravindg):

pi*r*r= area of circle

OpenStudy (aravindg):

here 2 pi r=A

OpenStudy (aravindg):

R=A/2PI

OpenStudy (aravindg):

AREA OF TRIANGLE =(1/2)*B/3*(B/3)

OpenStudy (jamesj):

Let C be the area of the circle. You need to write down that area as a function of A, C = C(A). And T = area triangle, T = T(B). What you just wrote isn't correct.

OpenStudy (aravindg):

y?

OpenStudy (jamesj):

Because the idea is once we know those functions, the combined area is C(A) + T(B) Write now x = A, then as A + B = 10, B = 10 - A = 10 - x. Hence the problem is now finding the global minimum of the function f(x) = C(x) + T(10-x). This is why we need the functions C and T. So find them.

OpenStudy (aravindg):

k find it

OpenStudy (jamesj):

The ball is in your court, as we say in English. Which means, I'm waiting now for you to say something. It's up to you to find C(A) and T(B). This part of the problem should be elementary, high school level work.

OpenStudy (anonymous):

if x is bent into a circle,what's the radius of this circle?

OpenStudy (jamesj):

Still waiting for your answer here :-)

OpenStudy (jamesj):

and to tell you honestly I'm not happy about helping you with another problem until I see you work one yourself. So I'd like to see work this one.

OpenStudy (aravindg):

i honestly dont know

OpenStudy (jamesj):

Show me. What is C(A), T(B) and f(x). Then what value of x minimizes f(x)

OpenStudy (aravindg):

i got it

OpenStudy (aravindg):

i found the value

OpenStudy (jamesj):

What is the function f(x) and what is that value of x?

OpenStudy (jamesj):

As A = 2.pi.r, r = A/(2.pi) hence C(A) = pi.r^2 = A^2/(4.pi) Now what's T(B)?

OpenStudy (aravindg):

R= 1-PI/PI+3ROOT3

OpenStudy (aravindg):

SRRY NOT 1- ITS 10

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