Question

Limits. Limits. @Mathematics

Answer 1

wanna chat?

Answer 2

Hey Karate. supp?

Answer 3

haha

Answer 4

o and what math is this?

Answer 5

Lol, this is something from Mars. i have no idea solving this..

Answer 6

no i mean like geometry calculus or algebra stats?

Answer 7

Calc.

Answer 8

hmmm

Answer 9

hmmm

Answer 10

i think i kno this

Answer 11

jk i was using an online solver but it said incomplete input

Answer 12

the answer to your limit(s) is 1

Answer 13

omg i guessed right!

Answer 14

\[\huge \lim_{x\to0} \frac{\ln(x+1)}{x}\]
We need to use L'Hopital's rule here because if we evaluate at zero, we have an indeterminate form:
\[\frac{\ln(0+1)}{0}=\frac{0}{0}\Rightarrow DNE\]

\[\huge \lim_{x\to0} \frac{\ln(x+1)}{x} = \lim_{x\to0} \frac{\frac{1}{x+1}}{1} = \fbox{1} \]

More about L'Hopital's rule and indeterminate forms here:: http://tutorial.math.lamar.edu/Classes/CalcI/LHospitalsRule.aspx

Hope this helps.