x/(x - 3) less than or equal to -8/(x - 6) Solve for x using any method
\[x \div(x - 3) \le -8/(x - 6)\]
I got to [(x - 1)(x + 2)]/[(x - 3)(x - 6) le 0 and dunno where to go from there.
I wish I could rage quit this class lol.
Your step wasn't exactly right. Look there: http://www.wolframalpha.com/input/?i=x%C3%B7%28x%E2%88%923%29%E2%89%A4%E2%88%928%2F%28x%E2%88%926%29
before all you need push the conditions that x not can be equal 3 and 6 becouse than those fractions are undefined so x/(x-3) +8/(x-6) <= 0 x(x-6)+8(x-3)<=0 x2-6x+8x-24<=0 x2 +2x -24<=0
x2 +2x -24=(x+6)(x-4)
so than x+6=0 so x=-6 and x-4=0 so x=4 those are zeros for this function
I'm trying to bring this all in lol
now you need check for what intervale(s) is less than zero - becous you know that for -6 and 4 is equal zero
hope that was understandably
???
Gimme a sec
How do I check for what you said to do with the intervals??
ok try
Try what? I'm confused!
why ? you know that for 3 and 6 those fractions are undefined and for -6 and 4 are zeros
Yeah so how do I solve for x from there?
now you need get in what intervale are less than zero
so one function when is less than zero ?
you know that just when for this value of x the resulted number is negativ - right ???
No I don't understand, I'm very sorry.
when one number is less than zero ?
comen i like to learned it
learne it sorry
what is your answer ?
sorry i need to go
Idk man I give up I have no idea what you're trying to tell me
why this is whery easy
your exercise what youn have wrote one function when is less or equal zero
becouse there is x/(x-3)+8/(x-6) <=0 after you add to both sides 8/(x-6)
I understand that the zeros are 4 and -6 and x can't = 3 or 6. I just dunno what the asnwer is from there
Fraction is <=0 when: 1. numerator is <=0 and denominator is >0 OR 2. numerator is >=0 and denominator is <0
now you need to check that for what intervale is less than zero ?
probe you understanding right what have wrote to you marina
I still don't get it lol omg this is so lame I give up.
I dont understand how to find the interval at all. This is going right over my head
Marina can you help this person ?
because i need to going now
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