Find the inverse of y=4x=1/3x-2. state the domain and range of the function and its inverse.Please show work

Question

anonymous · Answer

sorry it is y=4x+1/3x-2

anonymous · Answer

you have 2 equal sigh=ns

anonymous · Answer

ok so x = 4y + 1/3 y - 2
is the inverse
now sollve it for y

anonymous · Answer

since the original function is linear its domain and range are x $$\epsilon$$R and also y ... so in the invewrse the domain and range remain the same

zarkon · Answer

is the function $$y=\frac{4x+1}{3x-2}$$?

anonymous · Answer

yes

zarkon · Answer

then you should write it as 
y=(4x+1)/(3x-2)

so there is confusion.

zarkon · Answer

*is no confusion

anonymous · Answer

yes confusion

zarkon · Answer

writing 4x+1/3x-2 is the same as 

$$4x+\frac{1}{3}x-2$$

anonymous · Answer

my book just states find the invers of y=4x+1/3x-2. state the domain and range of the function and its inverse

anonymous · Answer

no it is divided by

anonymous · Answer

does that make sence

anonymous · Answer

it is stated y= 4x+1 divided by 3x-2

zarkon · Answer

ic

zarkon · Answer

solve $$x=\frac{4y+1}{3y-2}$$for $$y$$

anonymous · Answer

yes and I am not sure how. I am so new at this I am confused

zarkon · Answer

$$x=\frac{4y+1}{3y-2}$$

$$x(3y-2)=4y+1$$

$$3xy-2x=4y+1$$

$$3xy-4y=2x+1$$

$$(3x-4)y=2x+1$$

$$y=\frac{2x+1}{3x-4}$$

anonymous · Answer

Thank you now I have one to look at to do the rest.