Question

Find the critical numbers of the function, round your answer to three decimal places
s(t) = 3t^4 + 4t^3 − 18t^2

Answer 1

Critical numbers come or by setting the first derivaitve of the function to be zero. Have you found the derivative of this function?

Answer 2

yes, it would be s'(t)=12t^3+12t^2-36t

Answer 3

now you have to set that to zero and solve for x

Answer 4

so its, 12(t^2+t-3)=0

Answer 5

now, can that quadratice in the parenthesi be factored?

Answer 6

no you would have to use the quadratic formula

Answer 7

then that is what you must do. Thats why, they say to round

Answer 8

ok so i did it and got \[-1\pm \sqrt{-11} / 2\] is that right

Answer 9

something seems alittle bit off on your calculations, cause i get: