Find the critical numbers of the function, round your answer to three decimal places
s(t) = 3t^4 + 4t^3 − 18t^2

Question

anonymous · Answer

Critical numbers come or by setting the first derivaitve of the function to be zero. Have you found the derivative of this function?

anonymous · Answer

yes, it would be s'(t)=12t^3+12t^2-36t

anonymous · Answer

now you have to set that to zero and solve for x

anonymous · Answer

so its, 12(t^2+t-3)=0

anonymous · Answer

now, can that quadratice in the parenthesi be factored?

anonymous · Answer

no you would have to use the quadratic formula

anonymous · Answer

then that is what you must do. Thats why, they say to round

anonymous · Answer

ok so i did it and got $$-1\pm \sqrt{-11} / 2$$ is that right

anonymous · Answer

something seems alittle bit off on your calculations, cause i get:
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