rationalize the denominator
^3sqrt5y^4/^3sqrt15x^4

Question

turingtest · Answer

someday I hope you will learn to use the equation feature...$$\sqrt[3]5y^4\over \sqrt[3]15x^4$$or$$\sqrt[3]{5y^4}\over \sqrt[3]{15x^4}$$???

anonymous · Answer

they both look the same to me

turingtest · Answer

are the variable under the radical or just the numbers?

anonymous · Answer

its written how you have it written with a thin line not bold

turingtest · Answer

I don't understand, is it the first way I posted it or the second?

anonymous · Answer

yes the 1rst

turingtest · Answer

$${\sqrt[3]5y^4\over \sqrt[3]{15}x^4}={y^4\over \sqrt[3]3x^4}*{\sqrt[3]{3^2}\over \sqrt[3]{3^2}}={\sqrt[3]9y^4\over3x^4}$$sorry that took a while, I've never actually rationalized a non-square root before and had to figure it out.

anonymous · Answer

its okay thank you :D