Question

I have done this problem, and only get a part of the answer according to the answer sheet. Can someone please explain how to do this, thanks.

Question: Find an equation of the tangent line to the graph of F at the point (2,f(2)). Using the equation: F(x): = 2(x^2-1)^3 // I Know to use the chain rule and after I differentiate and input (2) I get F(x)=216. But the answer is Y=216x-378.

I haven't taken math in a while, and I'm trying to teach myself Calc. So an explanation will go a long way! I have done this problem, and only get a part of the answer according to the answer sheet. Can someone please explain how to do this, thanks.

Question: Find an equation of the tangent line to the graph of F at the point (2,f(2)). Using the equation: F(x): = 2(x^2-1)^3 // I Know to use the chain rule and after I differentiate and input (2) I get F(x)=216. But the answer is Y=216x-378.

I haven't taken math in a while, and I'm trying to teach myself Calc. So an explanation will go a long way! @Mathematics

Answer 1

The thing is that the first derivative gives you the slope of the tangent. So you correctly found that it was 216. Now you know that the tangent goes through the point (2,f(2)). So you can find the equation of the line through that point whose slope is 216

Answer 2

so Y1-Y= M (X1-X)?