Question

Subtract. simplify by removing a factor of 1 when possible.
(10pd)/(p^2-d^2)-(p-d)/(p+d)

Answer 1

\[\frac{10pd}{p^2-d^2}-\frac{p-d}{p+d}=\frac{10dp}{(p-q)(p+q)}-\frac{p-d}{p+d}\]

Answer 2

find a common denominator

Answer 3

then combine fractions

Answer 4

multiply 2nd fraction by (p-d)/(p-d)

Answer 5

let me know if you have anymore trouble

Answer 6

wuts the answer?

Answer 7

have you multiplied the 2nd fraction by (p-d)/(p-d) yet?

Answer 8

now the denominators are the same

so the numerator is 10dp-(p-d)(p-d)

Answer 9

simplify the numerator i gave you and let me know what you get
i will check it

Answer 10

i got 12dp-p^2-d^2

Answer 11

no thats not right
(p-d)(p-d)=p^2-dp-dp+d^2=p^2-2pd+d^2

Answer 12

so the numerator is 12dp-(p^2-2dp+d^2)

Answer 13

now distribute the negative 1
and combine like terms
and see if you can factor and cancel anything

Answer 14

14dp-p^2-d^2

Answer 15

yes very good

Answer 16

thats the numerator

Answer 17

and the denominator was (p-d)(p+d)

Answer 18

ok so the answer is...
(14dp-p^2-d^2)/(p-d)(p+d)?

Answer 19

hey i made a type-o and i didn't realize
that was a 10 not a 12
do you know what i'm talking about?

Answer 20

not realy.

Answer 21

10dp-(p^2-2dp+d^2)
10dp-p^2+2pd-d^2
12dp-p^2+d^2 is numerator
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above you have in your problem 10dp not 12dp

Answer 22

????????????

Answer 23

your problem has 10dp not 12dp
its the numerator of the first fraction
do you still not see it?

Answer 24

ok i think i see wut ur talkin about

Answer 25

\[\frac{10dp}{p^2-d^2}-\frac{p-d}{p+d}\]
this is your problem see its 10dp not 12dp

so the numerator was is 10dp-(p-d)(p-d)
which we already simpflied

Answer 26

oooo kk

Answer 27

and i'm saying i made a type-o and wrote 12dp-(p-d)(p-d)

Answer 28

it is 10dp-(p-d)(p-d)

Answer 29

kk

Answer 30

so the answer is
(12dp-p^2-d^2)/(p-d)(p+d)?

Answer 31

IS THAT THE RIGHT ANSWER?