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Mathematics 7 Online
OpenStudy (anonymous):

how do you determine the nature of the solutions in a problem for example you have a problem x^20+20=0 how do you find out what the natur eof the solution is either 1 real solution, 2 real solutions or 2 imaginary solutions? how do you determine the nature of the solutions in a problem for example you have a problem x^20+20=0 how do you find out what the natur eof the solution is either 1 real solution, 2 real solutions or 2 imaginary solutions? @Mathematics

OpenStudy (anonymous):

Well you can use the qudratic formula b^2-4ac if b^2-4ac >- then it has 2 real solution if b^2-4ac=0 then it has 1 real solution if b^2<0 then it has no real solutions.

OpenStudy (anonymous):

Oh x^20 I'm not too sure.

OpenStudy (anonymous):

Okay, so x^20=-20, right? But x^20 can only give a positive number (similar to how x^2 only gives a positive). Therefore, x^20 is not possible and you have no real solutions.

OpenStudy (anonymous):

I see you online, do you not get it? Don't be afraid, I'm not a pedobear, cute girl.

OpenStudy (anonymous):

Basically, anything to the exponent of an even number HAS to give a positive number.

OpenStudy (anonymous):

no its ^2 sorry

OpenStudy (anonymous):

i accidnetly pushed the 0 didnt mean to and yes i am still online i was washing dishes

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