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Write the expression below as a single logarithm. Please show all of your work. ln(xz^2)-3ln(x^3y)-1/2lnz Write the expression below as a single logarithm. Please show all of your work. ln(xz^2)-3ln(x^3y)-1/2lnz @Mathematics
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ln(xz^2/ [(x^3y)^3*z^(1/2)])
I came up with a different answer....mine was: loge(2^3/2/x^8y^3) Is that the same?
not it's not. when you combine logs, if you're subtracting it's division, addition is multiplication and any coefficients are exponents. so... alog(b)-clog(d) = log b^a/d^c
ok so my answer is probably wrong then? I used a calculator, but must have entered it wrong. Is what you put the correct answer?
you could simplify it to ln[ (z^(3/2)) / (x^5y^3) ]
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