Question

Express answers in simplest exact form.

A square with sides of 3sqrt2 is inscribed in a circle. What is the area of one of the sectors formed by the radii to the vertices of the square?

A = PI

Answer 1

A= ? PI

Answer 2

???

Answer 3

since sides of are \[3\sqrt{2}\] Diagonal length of the square is 6
that is nothing but the diameter of the circle
therefore required area = (area of the circle - area of the square)/4
= (9 . PI - 18) /4
=2.56