This term 76 students pass the mathematics test. The number is decreased by 5% of the number of the last term. How many students pass the the test in the last term? This term 76 students pass the mathematics test. The number is decreased by 5% of the number of the last term. How many students pass the the test in the last term? @Mathematics
lets call the number of students that passed last terms test 'n'. now, if this term the number that passed fell by 5%, that means this terms total must be 95n/100. so you now solve for:\[\frac{95n}{100}=76\]
do you understand?
how you get 95n?
\[95 percent=\frac{95}{100}\]
if the number this term was same as last term, then it would be 100% of last terms total and could be written as:\[\frac{100n}{100}=n\]
a 5% drop means you are left with (100-5)% = 95%
Suppose the number of students that passed last year is n. Then 95% of n could be written as: .95n
Does that part make sense?
For example, if 100 passed last year, and only 95% of that number passed this year, then .95*100 = 95 passed this year
Another example, if 20 passed last year, and only 95% of that number passed this year, then .95*20 = 19 passed this year... etc
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