Question

Change the Cartesian double integral ∫1
−1∫−√1−x2
√1−x2 2
(1+x2+y2)2 dydx into an
equivalent polar integral and evaluate. Change the Cartesian double integral ∫1
−1∫−√1−x2
√1−x2 2
(1+x2+y2)2 dydx into an
equivalent polar integral and evaluate. @Mathematics

Answer 1

is this your integral?
\[\int\limits_{1}^{-1}\int\limits_{-\sqrt{(1-x^2)}}^{2} (1+x^2+y^2)^2dxdy\]

Answer 2

first integral is right the second should be \[\int\limits_{-\sqrt{1-x^2)}}^{\sqrt{1-x^2}}\]

then the 2 is over the (1+x^2+y^2)^2

Answer 3

\[\int\limits_{-1}^{1}\int\limits_{-\sqrt{1-x^2}}^{\sqrt{1-x^2}} {2 \over (1+x^2+y^2)^2} dxdy \]