Question

Find the distance between the x and y intercepts of 7x-21y=8. Please show your work.

Answer 1

\[\sqrt{\left(-\frac{8}{21}\right)^2+\left(\frac{8}{7}\right)^2}=\frac{8 \sqrt{10}}{21}=1.205 \]

Answer 2

7 x - 21 y - 8 = 0
Set x to zero and solve for y. Again with y zero solve for x.

Answer 3

y-intercept -> set x to 0
21y=8
y=8/21
point (0,8/21)

x-intercept -> set y to 0
7x=8
x=8/7
point (8/7,0)

\[distance=\sqrt{(x _{1}-x _{2})^{2}+(y _{1}-y _{2})^{2}}\]
\[=\sqrt{(-\frac{8}{7})^{2}+(\frac{8}{21})^{2}}\]
\[\approx1.438\]

Answer 4

1.205 is right... I entered it in my calculator wrong.

Answer 5

zarkon can i get some help ? on my post

Answer 6

That can happen. I use Mathematica, a program that, so far, has never made a mistake.

Answer 7

thanks

Answer 8

yw

Answer 9

Mathematica rules!