Question

Use the quadratic formula to find the zeros of the function y = 2x2 + 3x + 6. Round to the nearest tenth if necessary.
A. {-1.7, 2.3}
B. {-2.4, 2.4}
C. {-2.3, 0.8}
D. no real solution

Answer 1

do you know the quadratic formula, meow?

Answer 2

formula for this one
use
\[x=\frac{-3\pm\sqrt{3^2-4\times 2\times 6}}{2\times 2}\]

Answer 3

once you see that the number under the radical is negative (clearly) you will say "no solution"

Answer 4

don't forget, as corky said, solution to
\[ax^2+bc+c=0\] is
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]