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Use the quadratic formula to find the zeros of the function y = 2x2 + 3x + 6. Round to the nearest tenth if necessary. A. {-1.7, 2.3} B. {-2.4, 2.4} C. {-2.3, 0.8} D. no real solution
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do you know the quadratic formula, meow?
formula for this one use \[x=\frac{-3\pm\sqrt{3^2-4\times 2\times 6}}{2\times 2}\]
once you see that the number under the radical is negative (clearly) you will say "no solution"
don't forget, as corky said, solution to \[ax^2+bc+c=0\] is \[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]
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