Question

Find the differential
y = ln*sqrt(1+x^2)

Answer 1

\[y=\ln \sqrt{1+x ^{2}}\]

Answer 2

can u help?

Answer 3

x/(x^2+1)

Answer 4

how did u get that

Answer 5

think it should be
\[\frac{2x}{x^2+1}\] by the chain rule

Answer 6

i know the chain rule is der of first*sec + 1st* der of 2nd but how did u get taht as ur derivative

Answer 7

derivative of lnx = 1/x so derivative of lnsqrt(1+x^2) is 1/sqrt(1+x^2). But then you have to multiply by the derivative of sqrt(1+x^2) which is 1/2sqrt(1+x^2)^-.5(2x) or
[xsqrt(1+x^2)-.5]1/sqrt(1+x^2)]=x/x^2+1

Answer 8

how about differentiate e^x/10
i know e^x is e^x