Question

My very last question for today. Help needed.

3 consecutive even integers are such that the sum of the smaller two equals six more than the largest one. Find the integers.

Answer 1

so y = 2+x ; x = 2+z ; and z+x = y+6

Answer 2

now just substitute and solve

Answer 3

The first number: x ==> smallest integer
The second number:x+2 ==>middle integer
The third number:x+4 ==> largest integer

(x)+ (x+2)=6+ (x+4) ==> equation

now just solve it...

x+x+2=6+x+4

2x+2=6+x+4

2x-x=6-2+4

x=8

the intergers are: 8, 10, 12

Answer 4

Thanks a LOT! This made my day ^.^
Thanks Thanks.

Answer 5

lol, no problem! =D