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\[^{x2} +4x + 4\ge 9\]
To mathteacher: Because 2 is divisible by 4.
subtract 9 from both sides:\[x ^{2}+4x -5 \ge 0\]this should now be solvable
hint: factor the above
x^2 +4x +4 >= 9 subtract 9 from both sides x^2 +4x -5 >= 0 factor the polynomial on the left Can you factor that polynomial?
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thats where i got stuck at
Is it factoring polynomials in general or factoring this *specific* polynomial that gives you trouble?
in general
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