Question

lim x-> pi/4 of (1-tanx)/(sinx-cosx)

Answer 1

\[\lim_{x \rightarrow \pi/4}\] \[(1-\tan x)/(\sin x-\cos x)\]

Answer 2

i'm not very good at limits
but tan pi/4 = 1 so 1- tanx -- > 0

Answer 3

\[ 1 - \tan x = 1 - (\sin x / \cos x) = \frac{\cos x - \sin x}{\cos x} \]

Given that, can you see how to proceed?

Answer 4

how did you get the cos x - sin x in the numerator?

Answer 5

Cmon. I'm writing down the expression with a common denominator, cos x

Answer 6

\[1 = \frac{ \cos x}{ \cos x} \]

Answer 7

thanks. so is the answer - root2

Answer 8

/

Answer 9

exactly.

Answer 10

yayy! thanks