How do we know which function is dominant of lnx/x^(1/2) using l'hopitals rule
Thanks for coming to help
Oh man, read this, read this RIGHT NOW -- it is an awesome introduction to relative rates of growth! http://www.math.psu.edu/ug/courses/math141
(scroll down and read the PDF titled "relative rates of growth". )
ok
HUH I need to use l'hopitals rule
you know the rule right? you need to differentiate the numerator and the denominator to get the derivative if the function has an indeterminate form
Take the first derivative of the numerator and denomiator separately, then take the limit as x goes to + and - infinity separately.
right so you wld differentiate them as if they were two separate functions
and then what wld u do?
then you right them as u'/v' which is your answer if the original fraction was u/v and where u' is the derivative of u
ok
also if that form also turns out to be an indeterminate form then you go on to differentiate them over again following till the time it is not an indeterminate form
ok
i believe you know the differentiation of the functions :) So you can go about the question right? :D
and then how do I know which one is dominant?
like the numerator or the denomanator?
dominant? i dont get you?
Evaluate the limit as x-> infinity. If it is infinity the top is dominant, if it is 0, the bottom is dominant. Use l'hopitals rule to find the limit.
Thnaks that is what i wanted!!!!!!!
My book is so stupid
It just gives one exxample and says which one is dominant but doesn't explain y
I had the same problem throughout my studies, some things in maths take a good hard think about before you can get them, so dont be discouraged :)
Thanks
What level of math r u in?
I'm a graduate :) you?
oh i am an undergraduate working to get my math major
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