How do I name: Fe(ClO)3, TiO2, and Mn(HPO4)2?
I got Fe(ClO)3 - iron (III) hypochlorate or iron (III) chlorate TiO2 - Titanium dioxide Mn(HPO4)2 - managanese (II) monohydrogen phosphate ion
I am so confused with when i should use the roman numerals, the "mono, penta, tetra, di," and ahhh.
ClO3- is chlorate, ClO2- is chlorite, and ClO- is hypochlorite. Fe(ClO)3 is therefore iron (III) hypochlorite or ferric hypochlorite. Titanium dioxide is correct. Are you sure it isn't Mn(H2PO4)2? That would be manganese biphosphate.
ohhh.. i see.
noo it's Mn(HPO4)2
how did you know about ferric? please gelp me understand D:
Roman numerals are used in an ionic bond when a metal ion (usually a transition metal) can have more than one valence. For example, iron can be +2 or +3, so you specify the valence in brackets. The prefixes are usually used for bonds between two non-metals to denote the number of each kind of atom. For example, SO3 is sulfur trioxide (mono isn't usually used as a prefix - i.e. not monosulfur trioxide). According to these rules, TiO2 should technically be called titanium (IV) oxide, which it is, because titanium can have more than one valence. However, in this case, you could also say titanium dioxide because the presence of two O's (-4 charge in total) implies that Ti must have a charge of +4.
ohhh... i see :P
;cause like I had some questions like: (NH4)2CO3, which I answered with ammonium carbonate and Pb(CN)4 - lead (IV) cyanide
-ic and -ous suffixes are an older method used to differentiate between multiple valences the same as putting the roman numerals in brackets. However, it only works for a few elements that have only two valences, with -ic corresponding to the higher valence and -ous corresponding to the lower valence. For example, stannous it tin (II) and stannic is tin (IV). This rule doesn't work for metals that have 3 or more valences, which is why the bracketed roman numerals are preferred.
Yes you're right - ionic bonds, you usually don't have to put in those prefixes, because the charges are obvious and therefore so are the numbers of each atom.
ohhhhhh... I get it! :3 Thank you!! :D
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