x^2/7 -x = 1/7 use quadratic formula? help me understand this, please? :) Thanks
You know the quadratic formula right?
yup :) its just the near to last part that screws me up :(
and the dumb fractions which i detest :/
If you could, If you would, Please show an ywork you've done? My little son?
(Nothing rhymed with star; I went with what I got)
o.O
err i dont know what to do with the x^2 :(
Wait...That's x to the exponent 2?
yes ^^
You can rewrite it like this \[\frac{1}{7}x^2 - x - \frac{1}{7}\] and then use quadratic formula
I think it just becomes a=1 in the quadratic formula.
Then you can factor out a 1/7 leaving you with this\[(x^2 - 7x - 1)\]
Can't disagree with that beautiful trinomial.
Can I? I dunno.
\[x^{2}/7-x=1/7\]
^^ yes but i moved the 1/7 over to the other side and factored out a 1/7 leaving you with what i wrote above.
Use the Quadratic Formula to find the solutions of \[x^2 - 7x - 1 = 0\]
You should get \[\frac{7 \pm 3 \sqrt{5}}{2}\]
So the final answer will look like the above?
Yes
ok thanks :)
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