find the value of theta Please answer clearly and explain the solution clearly and easy to understand. Thanks! (guaranteed medal for a good answer)
\[3\cos ^{2}\theta-7\cos \theta+4=0\]
Let cos(x) = b 3b^2 - 7b + 4 = 0 Solve b
WTF wikipedia?
You should probably get four answers
b=1, b=4/3
\[0\le \theta \le 2 \pi\]
could there be an undefined solution for the b=4/3
cos theta = 1 theta = 0, 2pi
because there is no cosine that has a value of 4/3 right?
so that is the only answer?
It's undefined because cos theta = Adjacent over hypotenuse hypotenuse is never greater than the adjacent (leg)
probably Remember to press good answer.
so cos, sin and tan should never have a value greater than 1?
For tan you can But not for cos or sin
ohh i see because tan =y/x Thanks!
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