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OpenStudy (moongazer):
find the value of theta
Please answer clearly and explain the solution clearly and easy to understand. Thanks!
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OpenStudy (moongazer):
\[3\cos ^{2}\theta-7\cos \theta+4=0\]
OpenStudy (anonymous):
Let cos(x) = b
3b^2 - 7b + 4 = 0
Solve b
OpenStudy (anonymous):
WTF wikipedia?
OpenStudy (anonymous):
You should probably get four answers
OpenStudy (moongazer):
b=1, b=4/3
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OpenStudy (moongazer):
\[0\le \theta \le 2 \pi\]
OpenStudy (moongazer):
could there be an undefined solution for the b=4/3
OpenStudy (anonymous):
cos theta = 1
theta = 0, 2pi
OpenStudy (moongazer):
because there is no cosine that has a value of 4/3 right?
OpenStudy (moongazer):
so that is the only answer?
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OpenStudy (anonymous):
It's undefined because cos theta = Adjacent over hypotenuse
hypotenuse is never greater than the adjacent (leg)
OpenStudy (anonymous):
probably
Remember to press good answer.
OpenStudy (moongazer):
so cos, sin and tan should never have a value greater than 1?
OpenStudy (anonymous):
For tan you can
But not for cos or sin
OpenStudy (moongazer):
ohh i see because tan =y/x
Thanks!
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