NEED HELP REALLY BAD Find that probability that a point chosen at random in the figure lies in the Green circle. The Green Circle has a diameter of 24. (The Green Circle is in the Blue Square)
What's the area of the square, call it S? And what's the area of the circle, call it C? Then the probability of being in the green is \[ \frac{C}{S} \]
it would be 24 right
Area of circle is 2 PI r and 12 is radius
its 75
Area of the circle is \( C = \pi r^2 \)
The area of the square is the length of the side, call it L, squared. What is the length of the side? What is L?
24
Hence \( S = L^2 = 24^2 = ... \). Now what is \( r \) and hence what is the area of the circle, \( C \)?
452.38934211693022633862064719225
or simply round down to 452
Right, hence C/S = 452/576 = ...
0.78472222222222222222222222222222
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